Solve 31/3+13/4-12/3

$$3 \frac{ 1 }{ 3 } +1 \frac{ 3 }{ 4 } -1 \frac{ 2 }{ 3 }$$

Evaluate

$$\frac{41}{12}\approx 3.416666667$$

Solution Steps

Multiply 3 and 3 to get 9.

$$\frac{9+1}{3}+\frac{1\times 4+3}{4}-\frac{1\times 3+2}{3}$$

Add 9 and 1 to get 10.

$$\frac{10}{3}+\frac{1\times 4+3}{4}-\frac{1\times 3+2}{3}$$

Multiply 1 and 4 to get 4.

$$\frac{10}{3}+\frac{4+3}{4}-\frac{1\times 3+2}{3}$$

Add 4 and 3 to get 7.

$$\frac{10}{3}+\frac{7}{4}-\frac{1\times 3+2}{3}$$

Least common multiple of 3 and 4 is 12. Convert \frac{10}{3} and \frac{7}{4} to fractions with denominator 12.

$$\frac{40}{12}+\frac{21}{12}-\frac{1\times 3+2}{3}$$

Since \frac{40}{12} and \frac{21}{12} have the same denominator, add them by adding their numerators.

$$\frac{40+21}{12}-\frac{1\times 3+2}{3}$$

Add 40 and 21 to get 61.

$$\frac{61}{12}-\frac{1\times 3+2}{3}$$

Multiply 1 and 3 to get 3.

$$\frac{61}{12}-\frac{3+2}{3}$$

Add 3 and 2 to get 5.

$$\frac{61}{12}-\frac{5}{3}$$

Least common multiple of 12 and 3 is 12. Convert \frac{61}{12} and \frac{5}{3} to fractions with denominator 12.

$$\frac{61}{12}-\frac{20}{12}$$

Since \frac{61}{12} and \frac{20}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{61-20}{12}$$

Subtract 20 from 61 to get 41.

$$\frac{41}{12}$$

Factor

$$\frac{41}{2 ^ {2} \cdot 3} = 3\frac{5}{12} = 3.4166666666666665$$