Solve 39/14-55/7+310/21

$$3 \frac { 9 } { 14 } - 5 \frac { 5 } { 7 } + 3 \frac { 10 } { 21 }$$

Evaluate

$$\frac{59}{42}\approx 1.404761905$$

Solution Steps

Multiply 3 and 14 to get 42.

$$\frac{42+9}{14}-\frac{5\times 7+5}{7}+\frac{3\times 21+10}{21}$$

Add 42 and 9 to get 51.

$$\frac{51}{14}-\frac{5\times 7+5}{7}+\frac{3\times 21+10}{21}$$

Multiply 5 and 7 to get 35.

$$\frac{51}{14}-\frac{35+5}{7}+\frac{3\times 21+10}{21}$$

Add 35 and 5 to get 40.

$$\frac{51}{14}-\frac{40}{7}+\frac{3\times 21+10}{21}$$

Least common multiple of 14 and 7 is 14. Convert \frac{51}{14} and \frac{40}{7} to fractions with denominator 14.

$$\frac{51}{14}-\frac{80}{14}+\frac{3\times 21+10}{21}$$

Since \frac{51}{14} and \frac{80}{14} have the same denominator, subtract them by subtracting their numerators.

$$\frac{51-80}{14}+\frac{3\times 21+10}{21}$$

Subtract 80 from 51 to get -29.

$$-\frac{29}{14}+\frac{3\times 21+10}{21}$$

Multiply 3 and 21 to get 63.

$$-\frac{29}{14}+\frac{63+10}{21}$$

Add 63 and 10 to get 73.

$$-\frac{29}{14}+\frac{73}{21}$$

Least common multiple of 14 and 21 is 42. Convert -\frac{29}{14} and \frac{73}{21} to fractions with denominator 42.

$$-\frac{87}{42}+\frac{146}{42}$$

Since -\frac{87}{42} and \frac{146}{42} have the same denominator, add them by adding their numerators.

$$\frac{-87+146}{42}$$

Add -87 and 146 to get 59.

$$\frac{59}{42}$$

Factor

$$\frac{59}{2 \cdot 3 \cdot 7} = 1\frac{17}{42} = 1.4047619047619047$$