Solve 37/8-(x-31/8

$$3 \frac { 7 } { 8 } - ( x - 3 \frac { 1 } { 8 }$$

Evaluate

$$7-x$$

Solution Steps

Multiply 3 and 8 to get 24.

$$\frac{24+7}{8}-\left(x-\frac{3\times 8+1}{8}\right)$$

Add 24 and 7 to get 31.

$$\frac{31}{8}-\left(x-\frac{3\times 8+1}{8}\right)$$

Multiply 3 and 8 to get 24.

$$\frac{31}{8}-\left(x-\frac{24+1}{8}\right)$$

Add 24 and 1 to get 25.

$$\frac{31}{8}-\left(x-\frac{25}{8}\right)$$

To find the opposite of x-\frac{25}{8}, find the opposite of each term.

$$\frac{31}{8}-x-\left(-\frac{25}{8}\right)$$

The opposite of -\frac{25}{8} is \frac{25}{8}.

$$\frac{31}{8}-x+\frac{25}{8}$$

Since \frac{31}{8} and \frac{25}{8} have the same denominator, add them by adding their numerators.

$$\frac{31+25}{8}-x$$

Add 31 and 25 to get 56.

$$\frac{56}{8}-x$$

Divide 56 by 8 to get 7.

$$7-x$$

Expand

$$7-x$$

Solution Steps

Multiply 3 and 8 to get 24.

$$\frac{24+7}{8}-\left(x-\frac{3\times 8+1}{8}\right)$$

Add 24 and 7 to get 31.

$$\frac{31}{8}-\left(x-\frac{3\times 8+1}{8}\right)$$

Multiply 3 and 8 to get 24.

$$\frac{31}{8}-\left(x-\frac{24+1}{8}\right)$$

Add 24 and 1 to get 25.

$$\frac{31}{8}-\left(x-\frac{25}{8}\right)$$

To find the opposite of x-\frac{25}{8}, find the opposite of each term.

$$\frac{31}{8}-x-\left(-\frac{25}{8}\right)$$

The opposite of -\frac{25}{8} is \frac{25}{8}.

$$\frac{31}{8}-x+\frac{25}{8}$$

Since \frac{31}{8} and \frac{25}{8} have the same denominator, add them by adding their numerators.

$$\frac{31+25}{8}-x$$

Add 31 and 25 to get 56.

$$\frac{56}{8}-x$$

Divide 56 by 8 to get 7.

$$7-x$$