Solve 37/8+(61/4)=

$$3 \frac { 7 } { 8 } + ( 6 \frac { 1 } { 4 } ) =$$

Evaluate

$$\frac{81}{8}=10.125$$

Solution Steps

Multiply 3 and 8 to get 24.

$$\frac{24+7}{8}+\frac{6\times 4+1}{4}$$

Add 24 and 7 to get 31.

$$\frac{31}{8}+\frac{6\times 4+1}{4}$$

Multiply 6 and 4 to get 24.

$$\frac{31}{8}+\frac{24+1}{4}$$

Add 24 and 1 to get 25.

$$\frac{31}{8}+\frac{25}{4}$$

Least common multiple of 8 and 4 is 8. Convert \frac{31}{8} and \frac{25}{4} to fractions with denominator 8.

$$\frac{31}{8}+\frac{50}{8}$$

Since \frac{31}{8} and \frac{50}{8} have the same denominator, add them by adding their numerators.

$$\frac{31+50}{8}$$

Add 31 and 50 to get 81.

$$\frac{81}{8}$$

Factor

$$\frac{3 ^ {4}}{2 ^ {3}} = 10\frac{1}{8} = 10.125$$