Solve 37/6+31/3=

$$3 \frac { 7 } { 6 } + 3 \frac { 1 } { 3 } =$$

Evaluate

$$\frac{15}{2}=7.5$$

Solution Steps

Multiply 3 and 6 to get 18.

$$\frac{18+7}{6}+\frac{3\times 3+1}{3}$$

Add 18 and 7 to get 25.

$$\frac{25}{6}+\frac{3\times 3+1}{3}$$

Multiply 3 and 3 to get 9.

$$\frac{25}{6}+\frac{9+1}{3}$$

Add 9 and 1 to get 10.

$$\frac{25}{6}+\frac{10}{3}$$

Least common multiple of 6 and 3 is 6. Convert \frac{25}{6} and \frac{10}{3} to fractions with denominator 6.

$$\frac{25}{6}+\frac{20}{6}$$

Since \frac{25}{6} and \frac{20}{6} have the same denominator, add them by adding their numerators.

$$\frac{25+20}{6}$$

Add 25 and 20 to get 45.

$$\frac{45}{6}$$

Reduce the fraction \frac{45}{6} to lowest terms by extracting and canceling out 3.

$$\frac{15}{2}$$

Factor

$$\frac{3 \cdot 5}{2} = 7\frac{1}{2} = 7.5$$