Solve 37/15div11/12-38/15=

$$3 \frac { 7 } { 15 } \div 1 \frac { 1 } { 12 } - 3 \frac { 8 } { 15 } =$$

Evaluate

$$-\frac{1}{3}\approx -0.333333333$$

Solution Steps

Divide \frac{3\times 15+7}{15} by \frac{1\times 12+1}{12} by multiplying \frac{3\times 15+7}{15} by the reciprocal of \frac{1\times 12+1}{12}.

$$\frac{\left(3\times 15+7\right)\times 12}{15\left(1\times 12+1\right)}-\frac{3\times 15+8}{15}$$

Cancel out 3 in both numerator and denominator.

$$\frac{4\left(7+3\times 15\right)}{5\left(1+12\right)}-\frac{3\times 15+8}{15}$$

Multiply 3 and 15 to get 45.

$$\frac{4\left(7+45\right)}{5\left(1+12\right)}-\frac{3\times 15+8}{15}$$

Add 7 and 45 to get 52.

$$\frac{4\times 52}{5\left(1+12\right)}-\frac{3\times 15+8}{15}$$

Multiply 4 and 52 to get 208.

$$\frac{208}{5\left(1+12\right)}-\frac{3\times 15+8}{15}$$

Add 1 and 12 to get 13.

$$\frac{208}{5\times 13}-\frac{3\times 15+8}{15}$$

Multiply 5 and 13 to get 65.

$$\frac{208}{65}-\frac{3\times 15+8}{15}$$

Reduce the fraction \frac{208}{65} to lowest terms by extracting and canceling out 13.

$$\frac{16}{5}-\frac{3\times 15+8}{15}$$

Multiply 3 and 15 to get 45.

$$\frac{16}{5}-\frac{45+8}{15}$$

Add 45 and 8 to get 53.

$$\frac{16}{5}-\frac{53}{15}$$

Least common multiple of 5 and 15 is 15. Convert \frac{16}{5} and \frac{53}{15} to fractions with denominator 15.

$$\frac{48}{15}-\frac{53}{15}$$

Since \frac{48}{15} and \frac{53}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{48-53}{15}$$

Subtract 53 from 48 to get -5.

$$\frac{-5}{15}$$

Reduce the fraction \frac{-5}{15} to lowest terms by extracting and canceling out 5.

$$-\frac{1}{3}$$

Factor

$$-\frac{1}{3} = -0.3333333333333333$$