Solve 35/12+41/6

$$3 \frac { 5 } { 12 } + 4 \frac { 1 } { 6 }$$

Evaluate

$$\frac{91}{12}\approx 7.583333333$$

Solution Steps

Multiply 3 and 12 to get 36.

$$\frac{36+5}{12}+\frac{4\times 6+1}{6}$$

Add 36 and 5 to get 41.

$$\frac{41}{12}+\frac{4\times 6+1}{6}$$

Multiply 4 and 6 to get 24.

$$\frac{41}{12}+\frac{24+1}{6}$$

Add 24 and 1 to get 25.

$$\frac{41}{12}+\frac{25}{6}$$

Least common multiple of 12 and 6 is 12. Convert \frac{41}{12} and \frac{25}{6} to fractions with denominator 12.

$$\frac{41}{12}+\frac{50}{12}$$

Since \frac{41}{12} and \frac{50}{12} have the same denominator, add them by adding their numerators.

$$\frac{41+50}{12}$$

Add 41 and 50 to get 91.

$$\frac{91}{12}$$

Factor

$$\frac{7 \cdot 13}{2 ^ {2} \cdot 3} = 7\frac{7}{12} = 7.583333333333333$$