Solve 34/7+25/6=quad34/7-25/6=

$$3 \frac { 4 } { 7 } + 2 \frac { 5 } { 6 } = \quad 3 \frac { 4 } { 7 } - 2 \frac { 5 } { 6 } =$$

Verify

Solution Steps

Multiply both sides of the equation by 42, the least common multiple of 7,6.

$$6\left(3\times 7+4\right)+7\left(2\times 6+5\right)=6\left(3\times 7+4\right)-7\left(2\times 6+5\right)$$

Multiply 3 and 7 to get 21.

$$6\left(21+4\right)+7\left(2\times 6+5\right)=6\left(3\times 7+4\right)-7\left(2\times 6+5\right)$$

Add 21 and 4 to get 25.

$$6\times 25+7\left(2\times 6+5\right)=6\left(3\times 7+4\right)-7\left(2\times 6+5\right)$$

Multiply 6 and 25 to get 150.

$$150+7\left(2\times 6+5\right)=6\left(3\times 7+4\right)-7\left(2\times 6+5\right)$$

Multiply 2 and 6 to get 12.

$$150+7\left(12+5\right)=6\left(3\times 7+4\right)-7\left(2\times 6+5\right)$$

Add 12 and 5 to get 17.

$$150+7\times 17=6\left(3\times 7+4\right)-7\left(2\times 6+5\right)$$

Multiply 7 and 17 to get 119.

$$150+119=6\left(3\times 7+4\right)-7\left(2\times 6+5\right)$$

Add 150 and 119 to get 269.

$$269=6\left(3\times 7+4\right)-7\left(2\times 6+5\right)$$

Multiply 3 and 7 to get 21.

$$269=6\left(21+4\right)-7\left(2\times 6+5\right)$$

Add 21 and 4 to get 25.

$$269=6\times 25-7\left(2\times 6+5\right)$$

Multiply 6 and 25 to get 150.

$$269=150-7\left(2\times 6+5\right)$$

Multiply 2 and 6 to get 12.

$$269=150-7\left(12+5\right)$$

Add 12 and 5 to get 17.

$$269=150-7\times 17$$

Multiply -7 and 17 to get -119.

$$269=150-119$$

Subtract 119 from 150 to get 31.

$$269=31$$

Compare 269 and 31.

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