Solve 34/5-11/10div1/6+31/10

$$3 \frac { 4 } { 5 } - 1 \frac { 1 } { 10 } \div \frac { 1 } { 6 } + 3 \frac { 1 } { 10 }$$

Evaluate

$$\frac{3}{10}=0.3$$

Solution Steps

Multiply 3 and 5 to get 15.

$$\frac{15+4}{5}-\frac{\frac{1\times 10+1}{10}}{\frac{1}{6}}+\frac{3\times 10+1}{10}$$

Add 15 and 4 to get 19.

$$\frac{19}{5}-\frac{\frac{1\times 10+1}{10}}{\frac{1}{6}}+\frac{3\times 10+1}{10}$$

Divide \frac{1\times 10+1}{10} by \frac{1}{6} by multiplying \frac{1\times 10+1}{10} by the reciprocal of \frac{1}{6}.

$$\frac{19}{5}-\frac{\left(1\times 10+1\right)\times 6}{10}+\frac{3\times 10+1}{10}$$

Multiply 1 and 10 to get 10.

$$\frac{19}{5}-\frac{\left(10+1\right)\times 6}{10}+\frac{3\times 10+1}{10}$$

Add 10 and 1 to get 11.

$$\frac{19}{5}-\frac{11\times 6}{10}+\frac{3\times 10+1}{10}$$

Multiply 11 and 6 to get 66.

$$\frac{19}{5}-\frac{66}{10}+\frac{3\times 10+1}{10}$$

Reduce the fraction \frac{66}{10} to lowest terms by extracting and canceling out 2.

$$\frac{19}{5}-\frac{33}{5}+\frac{3\times 10+1}{10}$$

Since \frac{19}{5} and \frac{33}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{19-33}{5}+\frac{3\times 10+1}{10}$$

Subtract 33 from 19 to get -14.

$$-\frac{14}{5}+\frac{3\times 10+1}{10}$$

Multiply 3 and 10 to get 30.

$$-\frac{14}{5}+\frac{30+1}{10}$$

Add 30 and 1 to get 31.

$$-\frac{14}{5}+\frac{31}{10}$$

Least common multiple of 5 and 10 is 10. Convert -\frac{14}{5} and \frac{31}{10} to fractions with denominator 10.

$$-\frac{28}{10}+\frac{31}{10}$$

Since -\frac{28}{10} and \frac{31}{10} have the same denominator, add them by adding their numerators.

$$\frac{-28+31}{10}$$

Add -28 and 31 to get 3.

$$\frac{3}{10}$$

Factor

$$\frac{3}{2 \cdot 5} = 0.3$$