Solve 33(8x-3(x+4))/4=-xquadc=

$$3 \frac { 3 ( 8 x - 3 ( x + 4 ) ) } { 4 } = - x \quad c =$$

Solve for c

$$c=-\frac{45}{4}+\frac{27}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4.

$$3\times 3\left(8x-3\left(x+4\right)\right)=4\left(-x\right)c$$

Multiply 3 and 3 to get 9.

$$9\left(8x-3\left(x+4\right)\right)=4\left(-x\right)c$$

Use the distributive property to multiply -3 by x+4.

$$9\left(8x-3x-12\right)=4\left(-x\right)c$$

Combine 8x and -3x to get 5x.

$$9\left(5x-12\right)=4\left(-x\right)c$$

Use the distributive property to multiply 9 by 5x-12.

$$45x-108=4\left(-x\right)c$$

Swap sides so that all variable terms are on the left hand side.

$$4\left(-x\right)c=45x-108$$

Multiply 4 and -1 to get -4.

$$-4xc=45x-108$$

The equation is in standard form.

$$\left(-4x\right)c=45x-108$$

Divide both sides by -4x.

$$\frac{\left(-4x\right)c}{-4x}=\frac{45x-108}{-4x}$$

Dividing by -4x undoes the multiplication by -4x.

$$c=\frac{45x-108}{-4x}$$

Divide 45x-108 by -4x.

$$c=-\frac{45}{4}+\frac{27}{x}$$

Solve for x

$$x=\frac{108}{4c+45}$$

$$c\neq -\frac{45}{4}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4.

$$3\times 3\left(8x-3\left(x+4\right)\right)=4\left(-x\right)c$$

Multiply 3 and 3 to get 9.

$$9\left(8x-3\left(x+4\right)\right)=4\left(-x\right)c$$

Use the distributive property to multiply -3 by x+4.

$$9\left(8x-3x-12\right)=4\left(-x\right)c$$

Combine 8x and -3x to get 5x.

$$9\left(5x-12\right)=4\left(-x\right)c$$

Use the distributive property to multiply 9 by 5x-12.

$$45x-108=4\left(-x\right)c$$

Subtract 4\left(-x\right)c from both sides.

$$45x-108-4\left(-x\right)c=0$$

Multiply -1 and 4 to get -4.

$$45x-108-4\left(-1\right)xc=0$$

Multiply -4 and -1 to get 4.

$$45x-108+4xc=0$$

Add 108 to both sides. Anything plus zero gives itself.

$$45x+4xc=108$$

Combine all terms containing x.

$$\left(45+4c\right)x=108$$

The equation is in standard form.

$$\left(4c+45\right)x=108$$

Divide both sides by 45+4c.

$$\frac{\left(4c+45\right)x}{4c+45}=\frac{108}{4c+45}$$

Dividing by 45+4c undoes the multiplication by 45+4c.

$$x=\frac{108}{4c+45}$$