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\frac{\left(3\times 4+3\right)\times 8}{4\left(1\times 8+1\right)}
Divide \frac{3\times 4+3}{4} by \frac{1\times 8+1}{8} by multiplying \frac{3\times 4+3}{4} by the reciprocal of \frac{1\times 8+1}{8}.
\frac{2\left(3+3\times 4\right)}{1+8}
Cancel out 4 in both numerator and denominator.
\frac{2\left(3+12\right)}{1+8}
Multiply 3 and 4 to get 12.
\frac{2\times 15}{1+8}
Add 3 and 12 to get 15.
\frac{30}{1+8}
Multiply 2 and 15 to get 30.
\frac{30}{9}
Add 1 and 8 to get 9.
\frac{10}{3}
Reduce the fraction \frac{30}{9} to lowest terms by extracting and canceling out 3.