Solve 33/4*33/4+33/4*1/4=

$$3 \frac { 3 } { 4 } \cdot 3 \frac { 3 } { 4 } + 3 \frac { 3 } { 4 } \cdot \frac { 1 } { 4 } =$$

Evaluate

$$15$$

Solution Steps

Multiply \frac{3\times 4+3}{4} and \frac{3\times 4+3}{4} to get \left(\frac{3\times 4+3}{4}\right)^{2}.

$$\left(\frac{3\times 4+3}{4}\right)^{2}+\frac{3\times 4+3}{4}\times \frac{1}{4}$$

Multiply 3 and 4 to get 12.

$$\left(\frac{12+3}{4}\right)^{2}+\frac{3\times 4+3}{4}\times \frac{1}{4}$$

Add 12 and 3 to get 15.

$$\left(\frac{15}{4}\right)^{2}+\frac{3\times 4+3}{4}\times \frac{1}{4}$$

Calculate \frac{15}{4} to the power of 2 and get \frac{225}{16}.

$$\frac{225}{16}+\frac{3\times 4+3}{4}\times \frac{1}{4}$$

Multiply 3 and 4 to get 12.

$$\frac{225}{16}+\frac{12+3}{4}\times \frac{1}{4}$$

Add 12 and 3 to get 15.

$$\frac{225}{16}+\frac{15}{4}\times \frac{1}{4}$$

Multiply \frac{15}{4} times \frac{1}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{225}{16}+\frac{15\times 1}{4\times 4}$$

Do the multiplications in the fraction \frac{15\times 1}{4\times 4}.

$$\frac{225}{16}+\frac{15}{16}$$

Since \frac{225}{16} and \frac{15}{16} have the same denominator, add them by adding their numerators.

$$\frac{225+15}{16}$$

Add 225 and 15 to get 240.

$$\frac{240}{16}$$

Divide 240 by 16 to get 15.

$$15$$

Factor

$$3\times 5$$