Solve 32/5+13/4-23/4=

$$3 \frac { 2 } { 5 } + 1 \frac { 3 } { 4 } - 2 \frac { 3 } { 4 } =$$

Evaluate

$$\frac{12}{5}=2.4$$

Solution Steps

Multiply 3 and 5 to get 15.

$$\frac{15+2}{5}+\frac{1\times 4+3}{4}-\frac{2\times 4+3}{4}$$

Add 15 and 2 to get 17.

$$\frac{17}{5}+\frac{1\times 4+3}{4}-\frac{2\times 4+3}{4}$$

Multiply 1 and 4 to get 4.

$$\frac{17}{5}+\frac{4+3}{4}-\frac{2\times 4+3}{4}$$

Add 4 and 3 to get 7.

$$\frac{17}{5}+\frac{7}{4}-\frac{2\times 4+3}{4}$$

Least common multiple of 5 and 4 is 20. Convert \frac{17}{5} and \frac{7}{4} to fractions with denominator 20.

$$\frac{68}{20}+\frac{35}{20}-\frac{2\times 4+3}{4}$$

Since \frac{68}{20} and \frac{35}{20} have the same denominator, add them by adding their numerators.

$$\frac{68+35}{20}-\frac{2\times 4+3}{4}$$

Add 68 and 35 to get 103.

$$\frac{103}{20}-\frac{2\times 4+3}{4}$$

Multiply 2 and 4 to get 8.

$$\frac{103}{20}-\frac{8+3}{4}$$

Add 8 and 3 to get 11.

$$\frac{103}{20}-\frac{11}{4}$$

Least common multiple of 20 and 4 is 20. Convert \frac{103}{20} and \frac{11}{4} to fractions with denominator 20.

$$\frac{103}{20}-\frac{55}{20}$$

Since \frac{103}{20} and \frac{55}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{103-55}{20}$$

Subtract 55 from 103 to get 48.

$$\frac{48}{20}$$

Reduce the fraction \frac{48}{20} to lowest terms by extracting and canceling out 4.

$$\frac{12}{5}$$

Factor

$$\frac{2 ^ {2} \cdot 3}{5} = 2\frac{2}{5} = 2.4$$