Solve 32/4div(4-22/3)=

$$3 \frac { 2 } { 4 } \div ( 4 - 2 \frac { 2 } { 3 } ) =$$

Evaluate

$$\frac{21}{8}=2.625$$

Solution Steps

Multiply 3 and 4 to get 12.

$$\frac{\frac{12+2}{4}}{4-\frac{2\times 3+2}{3}}$$

Add 12 and 2 to get 14.

$$\frac{\frac{14}{4}}{4-\frac{2\times 3+2}{3}}$$

Reduce the fraction \frac{14}{4} to lowest terms by extracting and canceling out 2.

$$\frac{\frac{7}{2}}{4-\frac{2\times 3+2}{3}}$$

Multiply 2 and 3 to get 6.

$$\frac{\frac{7}{2}}{4-\frac{6+2}{3}}$$

Add 6 and 2 to get 8.

$$\frac{\frac{7}{2}}{4-\frac{8}{3}}$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{\frac{7}{2}}{\frac{12}{3}-\frac{8}{3}}$$

Since \frac{12}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{7}{2}}{\frac{12-8}{3}}$$

Subtract 8 from 12 to get 4.

$$\frac{\frac{7}{2}}{\frac{4}{3}}$$

Divide \frac{7}{2} by \frac{4}{3} by multiplying \frac{7}{2} by the reciprocal of \frac{4}{3}.

$$\frac{7}{2}\times \frac{3}{4}$$

Multiply \frac{7}{2} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 3}{2\times 4}$$

Do the multiplications in the fraction \frac{7\times 3}{2\times 4}.

$$\frac{21}{8}$$

Factor

$$\frac{3 \cdot 7}{2 ^ {3}} = 2\frac{5}{8} = 2.625$$