Solve 31/9*8/21*33/4

$$3 \frac { 1 } { 9 } \times \frac { 8 } { 21 } \times 3 \frac { 3 } { 4 }$$

Evaluate

$$\frac{40}{9}\approx 4.444444444$$

Solution Steps

Multiply 3 and 9 to get 27.

$$\frac{27+1}{9}\times \frac{8}{21}\times \frac{3\times 4+3}{4}$$

Add 27 and 1 to get 28.

$$\frac{28}{9}\times \frac{8}{21}\times \frac{3\times 4+3}{4}$$

Multiply \frac{28}{9} times \frac{8}{21} by multiplying numerator times numerator and denominator times denominator.

$$\frac{28\times 8}{9\times 21}\times \frac{3\times 4+3}{4}$$

Do the multiplications in the fraction \frac{28\times 8}{9\times 21}.

$$\frac{224}{189}\times \frac{3\times 4+3}{4}$$

Reduce the fraction \frac{224}{189} to lowest terms by extracting and canceling out 7.

$$\frac{32}{27}\times \frac{3\times 4+3}{4}$$

Multiply 3 and 4 to get 12.

$$\frac{32}{27}\times \frac{12+3}{4}$$

Add 12 and 3 to get 15.

$$\frac{32}{27}\times \frac{15}{4}$$

Multiply \frac{32}{27} times \frac{15}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{32\times 15}{27\times 4}$$

Do the multiplications in the fraction \frac{32\times 15}{27\times 4}.

$$\frac{480}{108}$$

Reduce the fraction \frac{480}{108} to lowest terms by extracting and canceling out 12.

$$\frac{40}{9}$$

Factor

$$\frac{2 ^ {3} \cdot 5}{3 ^ {2}} = 4\frac{4}{9} = 4.444444444444445$$