Solve 31/9div21/9

$$3 \frac { 1 } { 9 } \div 2 \frac { 1 } { 9 }$$

Evaluate

$$\frac{28}{19}\approx 1.473684211$$

Solution Steps

Divide \frac{3\times 9+1}{9} by \frac{2\times 9+1}{9} by multiplying \frac{3\times 9+1}{9} by the reciprocal of \frac{2\times 9+1}{9}.

$$\frac{\left(3\times 9+1\right)\times 9}{9\left(2\times 9+1\right)}$$

Cancel out 9 in both numerator and denominator.

$$\frac{1+3\times 9}{1+2\times 9}$$

Multiply 3 and 9 to get 27.

$$\frac{1+27}{1+2\times 9}$$

Add 1 and 27 to get 28.

$$\frac{28}{1+2\times 9}$$

Multiply 2 and 9 to get 18.

$$\frac{28}{1+18}$$

Add 1 and 18 to get 19.

$$\frac{28}{19}$$

Factor

$$\frac{2 ^ {2} \cdot 7}{19} = 1\frac{9}{19} = 1.4736842105263157$$