Solve 31/7+52/4

$$3 \frac { 1 } { 7 } + 5 \frac { 2 } { 4 }$$

Evaluate

$$\frac{121}{14}\approx 8.642857143$$

Solution Steps

Multiply 3 and 7 to get 21.

$$\frac{21+1}{7}+\frac{5\times 4+2}{4}$$

Add 21 and 1 to get 22.

$$\frac{22}{7}+\frac{5\times 4+2}{4}$$

Multiply 5 and 4 to get 20.

$$\frac{22}{7}+\frac{20+2}{4}$$

Add 20 and 2 to get 22.

$$\frac{22}{7}+\frac{22}{4}$$

Reduce the fraction \frac{22}{4} to lowest terms by extracting and canceling out 2.

$$\frac{22}{7}+\frac{11}{2}$$

Least common multiple of 7 and 2 is 14. Convert \frac{22}{7} and \frac{11}{2} to fractions with denominator 14.

$$\frac{44}{14}+\frac{77}{14}$$

Since \frac{44}{14} and \frac{77}{14} have the same denominator, add them by adding their numerators.

$$\frac{44+77}{14}$$

Add 44 and 77 to get 121.

$$\frac{121}{14}$$

Factor

$$\frac{11 ^ {2}}{2 \cdot 7} = 8\frac{9}{14} = 8.642857142857142$$