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\frac{\left(3\times 5+1\right)\times 5}{5\left(2\times 5+2\right)}
Divide \frac{3\times 5+1}{5} by \frac{2\times 5+2}{5} by multiplying \frac{3\times 5+1}{5} by the reciprocal of \frac{2\times 5+2}{5}.
\frac{1+3\times 5}{2+2\times 5}
Cancel out 5 in both numerator and denominator.
\frac{1+15}{2+2\times 5}
Multiply 3 and 5 to get 15.
\frac{16}{2+2\times 5}
Add 1 and 15 to get 16.
\frac{16}{2+10}
Multiply 2 and 5 to get 10.
\frac{16}{12}
Add 2 and 10 to get 12.
\frac{4}{3}
Reduce the fraction \frac{16}{12} to lowest terms by extracting and canceling out 4.