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\frac{\left(3\times 3+1\right)\times 2}{3\left(2\times 2+1\right)}
Divide \frac{3\times 3+1}{3} by \frac{2\times 2+1}{2} by multiplying \frac{3\times 3+1}{3} by the reciprocal of \frac{2\times 2+1}{2}.
\frac{\left(9+1\right)\times 2}{3\left(2\times 2+1\right)}
Multiply 3 and 3 to get 9.
\frac{10\times 2}{3\left(2\times 2+1\right)}
Add 9 and 1 to get 10.
\frac{20}{3\left(2\times 2+1\right)}
Multiply 10 and 2 to get 20.
\frac{20}{3\left(4+1\right)}
Multiply 2 and 2 to get 4.
\frac{20}{3\times 5}
Add 4 and 1 to get 5.
\frac{20}{15}
Multiply 3 and 5 to get 15.
\frac{4}{3}
Reduce the fraction \frac{20}{15} to lowest terms by extracting and canceling out 5.