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\frac{\left(3\times 2+1\right)\times 5}{2\left(1\times 5+2\right)}
Divide \frac{3\times 2+1}{2} by \frac{1\times 5+2}{5} by multiplying \frac{3\times 2+1}{2} by the reciprocal of \frac{1\times 5+2}{5}.
\frac{\left(6+1\right)\times 5}{2\left(1\times 5+2\right)}
Multiply 3 and 2 to get 6.
\frac{7\times 5}{2\left(1\times 5+2\right)}
Add 6 and 1 to get 7.
\frac{35}{2\left(1\times 5+2\right)}
Multiply 7 and 5 to get 35.
\frac{35}{2\left(5+2\right)}
Multiply 1 and 5 to get 5.
\frac{35}{2\times 7}
Add 5 and 2 to get 7.
\frac{35}{14}
Multiply 2 and 7 to get 14.
\frac{5}{2}
Reduce the fraction \frac{35}{14} to lowest terms by extracting and canceling out 7.