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\frac{\left(3\times 2+1\right)\times 4}{2\left(1\times 4+1\right)}
Divide \frac{3\times 2+1}{2} by \frac{1\times 4+1}{4} by multiplying \frac{3\times 2+1}{2} by the reciprocal of \frac{1\times 4+1}{4}.
\frac{2\left(1+2\times 3\right)}{1+4}
Cancel out 2 in both numerator and denominator.
\frac{2\left(1+6\right)}{1+4}
Multiply 2 and 3 to get 6.
\frac{2\times 7}{1+4}
Add 1 and 6 to get 7.
\frac{14}{1+4}
Multiply 2 and 7 to get 14.
\frac{14}{5}
Add 1 and 4 to get 5.