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\frac{\frac{3\times 2+1}{2}}{1}\left(\frac{3}{4}-\frac{1}{2}\right)
Divide 2 by 2 to get 1.
\frac{\frac{6+1}{2}}{1}\left(\frac{3}{4}-\frac{1}{2}\right)
Multiply 3 and 2 to get 6.
\frac{\frac{7}{2}}{1}\left(\frac{3}{4}-\frac{1}{2}\right)
Add 6 and 1 to get 7.
\frac{7}{2}\left(\frac{3}{4}-\frac{1}{2}\right)
Anything divided by one gives itself.
\frac{7}{2}\left(\frac{3}{4}-\frac{2}{4}\right)
Least common multiple of 4 and 2 is 4. Convert \frac{3}{4} and \frac{1}{2} to fractions with denominator 4.
\frac{7}{2}\times \frac{3-2}{4}
Since \frac{3}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.
\frac{7}{2}\times \frac{1}{4}
Subtract 2 from 3 to get 1.
\frac{7\times 1}{2\times 4}
Multiply \frac{7}{2} times \frac{1}{4} by multiplying numerator times numerator and denominator times denominator.
\frac{7}{8}
Do the multiplications in the fraction \frac{7\times 1}{2\times 4}.