Solve 31/2+41/8=

$$3 \frac { 1 } { 2 } + 4 \frac { 1 } { 8 } =$$

Evaluate

$$\frac{61}{8}=7.625$$

Solution Steps

Multiply 3 and 2 to get 6.

$$\frac{6+1}{2}+\frac{4\times 8+1}{8}$$

Add 6 and 1 to get 7.

$$\frac{7}{2}+\frac{4\times 8+1}{8}$$

Multiply 4 and 8 to get 32.

$$\frac{7}{2}+\frac{32+1}{8}$$

Add 32 and 1 to get 33.

$$\frac{7}{2}+\frac{33}{8}$$

Least common multiple of 2 and 8 is 8. Convert \frac{7}{2} and \frac{33}{8} to fractions with denominator 8.

$$\frac{28}{8}+\frac{33}{8}$$

Since \frac{28}{8} and \frac{33}{8} have the same denominator, add them by adding their numerators.

$$\frac{28+33}{8}$$

Add 28 and 33 to get 61.

$$\frac{61}{8}$$

Factor

$$\frac{61}{2 ^ {3}} = 7\frac{5}{8} = 7.625$$