Solve for h
h=\frac{\sqrt[3]{x^{2}-1}}{3x}
x\neq 0
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3xh=\sqrt[3]{x^{2}-1}
The equation is in standard form.
\frac{3xh}{3x}=\frac{\sqrt[3]{x^{2}-1}}{3x}
Divide both sides by 3x.
h=\frac{\sqrt[3]{x^{2}-1}}{3x}
Dividing by 3x undoes the multiplication by 3x.
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