Solve 3*57+60*2*b=7*85x-10*55

$$3 \cdot 57 + 60 \cdot 2 \cdot b = 7 \cdot 85 x - 10 \cdot 55$$

Solve for b

$$b=\frac{119x}{24}-\frac{721}{120}$$

Steps for Solving Linear Equation

Do the multiplications.

$$171+120b=7\times 85x-10\times 55$$

Multiply 7 and 85 to get 595.

$$171+120b=595x-10\times 55$$

Multiply 10 and 55 to get 550.

$$171+120b=595x-550$$

Subtract 171 from both sides.

$$120b=595x-550-171$$

Subtract 171 from -550 to get -721.

$$120b=595x-721$$

Divide both sides by 120.

$$\frac{120b}{120}=\frac{595x-721}{120}$$

Dividing by 120 undoes the multiplication by 120.

$$b=\frac{595x-721}{120}$$

Divide 595x-721 by 120.

$$b=\frac{119x}{24}-\frac{721}{120}$$

Solve for x

$$x=\frac{24b}{119}+\frac{103}{85}$$

Steps for Solving Linear Equation

Do the multiplications.

$$171+120b=7\times 85x-10\times 55$$

Multiply 7 and 85 to get 595.

$$171+120b=595x-10\times 55$$

Multiply 10 and 55 to get 550.

$$171+120b=595x-550$$

Swap sides so that all variable terms are on the left hand side.

$$595x-550=171+120b$$

Add 550 to both sides.

$$595x=171+120b+550$$

Add 171 and 550 to get 721.

$$595x=721+120b$$

The equation is in standard form.

$$595x=120b+721$$

Divide both sides by 595.

$$\frac{595x}{595}=\frac{120b+721}{595}$$

Dividing by 595 undoes the multiplication by 595.

$$x=\frac{120b+721}{595}$$

Divide 721+120b by 595.

$$x=\frac{24b}{119}+\frac{103}{85}$$