Solve 3*3+[6+2*(2^3/4+3*2)-7*sqrt{4}]+9/3=

$$3 \cdot 3 + [ 6 + 2 * ( 2 ^ { 3 } / 4 + 3 * 2 ) - 7 \cdot \sqrt { 4 } ] + 9 / 3 =$$

Evaluate

$$20$$

Solution Steps

Multiply 3 and 3 to get 9.

$$9+6+2\left(\frac{2^{3}}{4}+3\times 2\right)-7\sqrt{4}+\frac{9}{3}$$

Add 9 and 6 to get 15.

$$15+2\left(\frac{2^{3}}{4}+3\times 2\right)-7\sqrt{4}+\frac{9}{3}$$

Calculate 2 to the power of 3 and get 8.

$$15+2\left(\frac{8}{4}+3\times 2\right)-7\sqrt{4}+\frac{9}{3}$$

Divide 8 by 4 to get 2.

$$15+2\left(2+3\times 2\right)-7\sqrt{4}+\frac{9}{3}$$

Multiply 3 and 2 to get 6.

$$15+2\left(2+6\right)-7\sqrt{4}+\frac{9}{3}$$

Add 2 and 6 to get 8.

$$15+2\times 8-7\sqrt{4}+\frac{9}{3}$$

Multiply 2 and 8 to get 16.

$$15+16-7\sqrt{4}+\frac{9}{3}$$

Add 15 and 16 to get 31.

$$31-7\sqrt{4}+\frac{9}{3}$$

Calculate the square root of 4 and get 2.

$$31-7\times 2+\frac{9}{3}$$

Multiply -7 and 2 to get -14.

$$31-14+\frac{9}{3}$$

Subtract 14 from 31 to get 17.

$$17+\frac{9}{3}$$

Divide 9 by 3 to get 3.

$$17+3$$

Add 17 and 3 to get 20.

$$20$$

Factor

$$2^{2}\times 5$$