Solve 3*2^3*sqrt{9+5}*8(4^2+4)=

$$3 \cdot 2 ^ { 3 } \cdot \sqrt { 9 + 5 } \cdot 8 ( 4 ^ { 2 } + 4 ) =$$

Evaluate

$$3840\sqrt{14}\approx 14367.964365212$$

Solution Steps

Multiply 3 and 8 to get 24.

$$24\times 2^{3}\sqrt{9+5}\left(4^{2}+4\right)$$

Calculate 2 to the power of 3 and get 8.

$$24\times 8\sqrt{9+5}\left(4^{2}+4\right)$$

Multiply 24 and 8 to get 192.

$$192\sqrt{9+5}\left(4^{2}+4\right)$$

Add 9 and 5 to get 14.

$$192\sqrt{14}\left(4^{2}+4\right)$$

Calculate 4 to the power of 2 and get 16.

$$192\sqrt{14}\left(16+4\right)$$

Add 16 and 4 to get 20.

$$192\sqrt{14}\times 20$$

Multiply 192 and 20 to get 3840.

$$3840\sqrt{14}$$