Solve 3*(x+5)^4=48quadj)sqrt[4]{3}

$$3 \cdot ( x + 5 ) ^ { 4 } = 48 \quad j ) \sqrt[ 4 ] { 3 }$$

Solve for j

$$j=\frac{\left(x+5\right)^{4}}{16}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$48j=3\left(x+5\right)^{4}$$

Divide both sides by 48.

$$\frac{48j}{48}=\frac{3\left(x+5\right)^{4}}{48}$$

Dividing by 48 undoes the multiplication by 48.

$$j=\frac{3\left(x+5\right)^{4}}{48}$$

Divide 3\left(x+5\right)^{4} by 48.

$$j=\frac{\left(x+5\right)^{4}}{16}$$

Solve for x (complex solution)

$$x=-2\sqrt[4]{j}-5$$

$$x=-2i\sqrt[4]{j}-5$$

$$x=2\sqrt[4]{j}-5$$

$$x=2i\sqrt[4]{j}-5$$

Solve for x

$$x=-2\sqrt[4]{j}-5$$

$$x=2\sqrt[4]{j}-5\text{, }j\geq 0$$