Solve 3*(1+3)^2+2^2+2^3

$$3 \cdot ( 1 + 3 ) ^ { 2 } + 2 ^ { 2 } + 2 ^ { 3 }$$

Evaluate

$$60$$

Solution Steps

Add 1 and 3 to get 4.

$$3\times 4^{2}+2^{2}+2^{3}$$

Calculate 4 to the power of 2 and get 16.

$$3\times 16+2^{2}+2^{3}$$

Multiply 3 and 16 to get 48.

$$48+2^{2}+2^{3}$$

Calculate 2 to the power of 2 and get 4.

$$48+4+2^{3}$$

Add 48 and 4 to get 52.

$$52+2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$52+8$$

Add 52 and 8 to get 60.

$$60$$

Factor

$$2^{2}\times 3\times 5$$