Solve 3*(1+3*(-14/5)-4*[(-14/5)-2)+3=

$$3 \cdot ( 1 + 3 \cdot ( - \frac { 14 } { 5 } ) - 4 \cdot [ ( - \frac { 14 } { 5 } ) - 2 ) + 3 =$$

Evaluate

$$\frac{222}{5}=44.4$$

Solution Steps

Express 3\left(-\frac{14}{5}\right) as a single fraction.

$$3\left(1+\frac{3\left(-14\right)}{5}-4\left(-\frac{14}{5}-2\right)+3\right)$$

Multiply 3 and -14 to get -42.

$$3\left(1+\frac{-42}{5}-4\left(-\frac{14}{5}-2\right)+3\right)$$

Fraction \frac{-42}{5} can be rewritten as -\frac{42}{5} by extracting the negative sign.

$$3\left(1-\frac{42}{5}-4\left(-\frac{14}{5}-2\right)+3\right)$$

Convert 1 to fraction \frac{5}{5}.

$$3\left(\frac{5}{5}-\frac{42}{5}-4\left(-\frac{14}{5}-2\right)+3\right)$$

Since \frac{5}{5} and \frac{42}{5} have the same denominator, subtract them by subtracting their numerators.

$$3\left(\frac{5-42}{5}-4\left(-\frac{14}{5}-2\right)+3\right)$$

Subtract 42 from 5 to get -37.

$$3\left(-\frac{37}{5}-4\left(-\frac{14}{5}-2\right)+3\right)$$

Convert 2 to fraction \frac{10}{5}.

$$3\left(-\frac{37}{5}-4\left(-\frac{14}{5}-\frac{10}{5}\right)+3\right)$$

Since -\frac{14}{5} and \frac{10}{5} have the same denominator, subtract them by subtracting their numerators.

$$3\left(-\frac{37}{5}-4\times \frac{-14-10}{5}+3\right)$$

Subtract 10 from -14 to get -24.

$$3\left(-\frac{37}{5}-4\left(-\frac{24}{5}\right)+3\right)$$

Express 4\left(-\frac{24}{5}\right) as a single fraction.

$$3\left(-\frac{37}{5}-\frac{4\left(-24\right)}{5}+3\right)$$

Multiply 4 and -24 to get -96.

$$3\left(-\frac{37}{5}-\frac{-96}{5}+3\right)$$

Fraction \frac{-96}{5} can be rewritten as -\frac{96}{5} by extracting the negative sign.

$$3\left(-\frac{37}{5}-\left(-\frac{96}{5}\right)+3\right)$$

The opposite of -\frac{96}{5} is \frac{96}{5}.

$$3\left(-\frac{37}{5}+\frac{96}{5}+3\right)$$

Since -\frac{37}{5} and \frac{96}{5} have the same denominator, add them by adding their numerators.

$$3\left(\frac{-37+96}{5}+3\right)$$

Add -37 and 96 to get 59.

$$3\left(\frac{59}{5}+3\right)$$

Convert 3 to fraction \frac{15}{5}.

$$3\left(\frac{59}{5}+\frac{15}{5}\right)$$

Since \frac{59}{5} and \frac{15}{5} have the same denominator, add them by adding their numerators.

$$3\times \frac{59+15}{5}$$

Add 59 and 15 to get 74.

$$3\times \frac{74}{5}$$

Express 3\times \frac{74}{5} as a single fraction.

$$\frac{3\times 74}{5}$$

Multiply 3 and 74 to get 222.

$$\frac{222}{5}$$

Factor

$$\frac{2 \cdot 3 \cdot 37}{5} = 44\frac{2}{5} = 44.4$$