Solve 3*(5/6+7/15)

$$3 \cdot ( \frac { 5 } { 6 } + \frac { 7 } { 15 } )$$

Evaluate

$$\frac{39}{10}=3.9$$

Solution Steps

Least common multiple of 6 and 15 is 30. Convert \frac{5}{6} and \frac{7}{15} to fractions with denominator 30.

$$3\left(\frac{25}{30}+\frac{14}{30}\right)$$

Since \frac{25}{30} and \frac{14}{30} have the same denominator, add them by adding their numerators.

$$3\times \frac{25+14}{30}$$

Add 25 and 14 to get 39.

$$3\times \frac{39}{30}$$

Reduce the fraction \frac{39}{30} to lowest terms by extracting and canceling out 3.

$$3\times \frac{13}{10}$$

Express 3\times \frac{13}{10} as a single fraction.

$$\frac{3\times 13}{10}$$

Multiply 3 and 13 to get 39.

$$\frac{39}{10}$$

Factor

$$\frac{3 \cdot 13}{2 \cdot 5} = 3\frac{9}{10} = 3.9$$