Solve 3*{2*[4-2*(-2)]+3*(1-10)}

$$3 \cdot \{ 2 \cdot [ 4 - 2 \cdot ( - 2 ) ] + 3 \cdot ( 1 - 10 ) \}$$

Evaluate

$$-33$$

Solution Steps

Multiply 2 and -2 to get -4.

$$3\left(2\left(4-\left(-4\right)\right)+3\left(1-10\right)\right)$$

The opposite of -4 is 4.

$$3\left(2\left(4+4\right)+3\left(1-10\right)\right)$$

Add 4 and 4 to get 8.

$$3\left(2\times 8+3\left(1-10\right)\right)$$

Multiply 2 and 8 to get 16.

$$3\left(16+3\left(1-10\right)\right)$$

Subtract 10 from 1 to get -9.

$$3\left(16+3\left(-9\right)\right)$$

Multiply 3 and -9 to get -27.

$$3\left(16-27\right)$$

Subtract 27 from 16 to get -11.

$$3\left(-11\right)$$

Multiply 3 and -11 to get -33.

$$-33$$

Factor

$$-33$$