Solve 3*4*5*6*7*58sqrt{52}

$$3 \cdot 4 \cdot 5 \cdot 6 \cdot 7 \times 58 \sqrt{ 52 }$$

Evaluate

$$292320\sqrt{13}\approx 1053974.748843633$$

Solution Steps

Multiply 3 and 4 to get 12.

$$12\times 5\times 6\times 7\times 58\sqrt{52}$$

Multiply 12 and 5 to get 60.

$$60\times 6\times 7\times 58\sqrt{52}$$

Multiply 60 and 6 to get 360.

$$360\times 7\times 58\sqrt{52}$$

Multiply 360 and 7 to get 2520.

$$2520\times 58\sqrt{52}$$

Multiply 2520 and 58 to get 146160.

$$146160\sqrt{52}$$

Factor 52=2^{2}\times 13. Rewrite the square root of the product \sqrt{2^{2}\times 13} as the product of square roots \sqrt{2^{2}}\sqrt{13}. Take the square root of 2^{2}.

$$146160\times 2\sqrt{13}$$

Multiply 146160 and 2 to get 292320.

$$292320\sqrt{13}$$