Solve for t
t=\log_{3}\left(29\right)\approx 3.065044752
Solve for t (complex solution)
t=\frac{2\pi n_{1}i}{\ln(3)}+\log_{3}\left(29\right)
n_{1}\in \mathrm{Z}
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3^{t}=29
Use the rules of exponents and logarithms to solve the equation.
\log(3^{t})=\log(29)
Take the logarithm of both sides of the equation.
t\log(3)=\log(29)
The logarithm of a number raised to a power is the power times the logarithm of the number.
t=\frac{\log(29)}{\log(3)}
Divide both sides by \log(3).
t=\log_{3}\left(29\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
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