Solve 3^4*(-3)^2+2^0-6^2

$$3 ^ { 4 } \cdot ( - 3 ) ^ { 2 } + 2 ^ { 0 } - 6 ^ { 2 }$$

Evaluate

$$694$$

Solution Steps

Calculate 3 to the power of 4 and get 81.

$$81\left(-3\right)^{2}+2^{0}-6^{2}$$

Calculate -3 to the power of 2 and get 9.

$$81\times 9+2^{0}-6^{2}$$

Multiply 81 and 9 to get 729.

$$729+2^{0}-6^{2}$$

Calculate 2 to the power of 0 and get 1.

$$729+1-6^{2}$$

Add 729 and 1 to get 730.

$$730-6^{2}$$

Calculate 6 to the power of 2 and get 36.

$$730-36$$

Subtract 36 from 730 to get 694.

$$694$$

Factor

$$2\times 347$$