Solve 3^3p-2*3^2+2*3=-3

$$3 ^ { 3 } p - 2 \cdot 3 ^ { 2 } + 2 \cdot 3 = - 3$$

Solve for p

$$p=\frac{1}{3}\approx 0.333333333$$

Steps for Solving Linear Equation

Calculate 3 to the power of 3 and get 27.

$$27p-2\times 3^{2}+2\times 3=-3$$

Calculate 3 to the power of 2 and get 9.

$$27p-2\times 9+2\times 3=-3$$

Multiply 2 and 9 to get 18.

$$27p-18+2\times 3=-3$$

Multiply 2 and 3 to get 6.

$$27p-18+6=-3$$

Add -18 and 6 to get -12.

$$27p-12=-3$$

Add 12 to both sides.

$$27p=-3+12$$

Add -3 and 12 to get 9.

$$27p=9$$

Divide both sides by 27.

$$p=\frac{9}{27}$$

Reduce the fraction \frac{9}{27} to lowest terms by extracting and canceling out 9.

$$p=\frac{1}{3}$$