Solve 3^{3}+3*5^2+2*3^2-4*(7^2*3-11^2+3)

$$3 ^ { 3 } + 3 \times 5 ^ { 2 } + 2 \times 3 ^ { 2 } - 4 \times ( 7 ^ { 2 } \times 3 - 11 ^ { 2 } + 3 )$$

Evaluate

$$4$$

Solution Steps

Calculate 3 to the power of 3 and get 27.

$$27+3\times 5^{2}+2\times 3^{2}-4\left(7^{2}\times 3-11^{2}+3\right)$$

Calculate 5 to the power of 2 and get 25.

$$27+3\times 25+2\times 3^{2}-4\left(7^{2}\times 3-11^{2}+3\right)$$

Multiply 3 and 25 to get 75.

$$27+75+2\times 3^{2}-4\left(7^{2}\times 3-11^{2}+3\right)$$

Add 27 and 75 to get 102.

$$102+2\times 3^{2}-4\left(7^{2}\times 3-11^{2}+3\right)$$

Calculate 3 to the power of 2 and get 9.

$$102+2\times 9-4\left(7^{2}\times 3-11^{2}+3\right)$$

Multiply 2 and 9 to get 18.

$$102+18-4\left(7^{2}\times 3-11^{2}+3\right)$$

Add 102 and 18 to get 120.

$$120-4\left(7^{2}\times 3-11^{2}+3\right)$$

Calculate 7 to the power of 2 and get 49.

$$120-4\left(49\times 3-11^{2}+3\right)$$

Multiply 49 and 3 to get 147.

$$120-4\left(147-11^{2}+3\right)$$

Calculate 11 to the power of 2 and get 121.

$$120-4\left(147-121+3\right)$$

Subtract 121 from 147 to get 26.

$$120-4\left(26+3\right)$$

Add 26 and 3 to get 29.

$$120-4\times 29$$

Multiply 4 and 29 to get 116.

$$120-116$$

Subtract 116 from 120 to get 4.

$$4$$

Factor

$$2^{2}$$