Solve 3^2-2^3+6div27

$$3 ^ { 2 } - 2 ^ { 3 } + 6 \div 27$$

Evaluate

$$\frac{11}{9}\approx 1.222222222$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9-2^{3}+\frac{6}{27}$$

Calculate 2 to the power of 3 and get 8.

$$9-8+\frac{6}{27}$$

Subtract 8 from 9 to get 1.

$$1+\frac{6}{27}$$

Reduce the fraction \frac{6}{27} to lowest terms by extracting and canceling out 3.

$$1+\frac{2}{9}$$

Convert 1 to fraction \frac{9}{9}.

$$\frac{9}{9}+\frac{2}{9}$$

Since \frac{9}{9} and \frac{2}{9} have the same denominator, add them by adding their numerators.

$$\frac{9+2}{9}$$

Add 9 and 2 to get 11.

$$\frac{11}{9}$$

Factor

$$\frac{11}{3 ^ {2}} = 1\frac{2}{9} = 1.2222222222222223$$