Solve 3^2-(4-3*2)+6+2*(2^4:4)

$$3 ^ { 2 } - ( 4 - 3 \cdot 2 ) + 6 + 2 \cdot ( 2 ^ { 4 } : 4 )$$

Evaluate

$$25$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9-\left(4-3\times 2\right)+6+2\times \frac{2^{4}}{4}$$

Multiply 3 and 2 to get 6.

$$9-\left(4-6\right)+6+2\times \frac{2^{4}}{4}$$

Subtract 6 from 4 to get -2.

$$9-\left(-2\right)+6+2\times \frac{2^{4}}{4}$$

The opposite of -2 is 2.

$$9+2+6+2\times \frac{2^{4}}{4}$$

Add 9 and 2 to get 11.

$$11+6+2\times \frac{2^{4}}{4}$$

Add 11 and 6 to get 17.

$$17+2\times \frac{2^{4}}{4}$$

Calculate 2 to the power of 4 and get 16.

$$17+2\times \frac{16}{4}$$

Divide 16 by 4 to get 4.

$$17+2\times 4$$

Multiply 2 and 4 to get 8.

$$17+8$$

Add 17 and 8 to get 25.

$$25$$

Factor

$$5^{2}$$