Solve 3^2-(15/13)^2+(15/13+1)^2=

$$3 ^ { 2 } - ( \frac { 15 } { 13 } ) ^ { 2 } + ( \frac { 15 } { 13 } + 1 ) ^ { 2 } =$$

Evaluate

$$\frac{160}{13}\approx 12.307692308$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9-\left(\frac{15}{13}\right)^{2}+\left(\frac{15}{13}+1\right)^{2}$$

Calculate \frac{15}{13} to the power of 2 and get \frac{225}{169}.

$$9-\frac{225}{169}+\left(\frac{15}{13}+1\right)^{2}$$

Subtract \frac{225}{169} from 9 to get \frac{1296}{169}.

$$\frac{1296}{169}+\left(\frac{15}{13}+1\right)^{2}$$

Add \frac{15}{13} and 1 to get \frac{28}{13}.

$$\frac{1296}{169}+\left(\frac{28}{13}\right)^{2}$$

Calculate \frac{28}{13} to the power of 2 and get \frac{784}{169}.

$$\frac{1296}{169}+\frac{784}{169}$$

Add \frac{1296}{169} and \frac{784}{169} to get \frac{160}{13}.

$$\frac{160}{13}$$

Factor

$$\frac{2 ^ {5} \cdot 5}{13} = 12\frac{4}{13} = 12.307692307692308$$