Solve 3^2*(-1/3)-3*(-1/3)^2

$$3 ^ { 2 } \times ( - \frac { 1 } { 3 } ) - 3 \times ( - \frac { 1 } { 3 } ) ^ { 2 }$$

Evaluate

$$-\frac{10}{3}\approx -3.333333333$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9\left(-\frac{1}{3}\right)-3\left(-\frac{1}{3}\right)^{2}$$

Express 9\left(-\frac{1}{3}\right) as a single fraction.

$$\frac{9\left(-1\right)}{3}-3\left(-\frac{1}{3}\right)^{2}$$

Multiply 9 and -1 to get -9.

$$\frac{-9}{3}-3\left(-\frac{1}{3}\right)^{2}$$

Divide -9 by 3 to get -3.

$$-3-3\left(-\frac{1}{3}\right)^{2}$$

Calculate -\frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$-3-3\times \frac{1}{9}$$

Multiply 3 and \frac{1}{9} to get \frac{3}{9}.

$$-3-\frac{3}{9}$$

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$-3-\frac{1}{3}$$

Convert -3 to fraction -\frac{9}{3}.

$$-\frac{9}{3}-\frac{1}{3}$$

Since -\frac{9}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-9-1}{3}$$

Subtract 1 from -9 to get -10.

$$-\frac{10}{3}$$

Factor

$$-\frac{10}{3} = -3\frac{1}{3} = -3.3333333333333335$$