Solve 3^2*2^2-4^3+5(3-5)^3

$$3 ^ { 2 } \cdot 2 ^ { 2 } - 4 ^ { 3 } + 5 ( 3 - 5 ) ^ { 3 }$$

Evaluate

$$-68$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9\times 2^{2}-4^{3}+5\left(3-5\right)^{3}$$

Calculate 2 to the power of 2 and get 4.

$$9\times 4-4^{3}+5\left(3-5\right)^{3}$$

Multiply 9 and 4 to get 36.

$$36-4^{3}+5\left(3-5\right)^{3}$$

Calculate 4 to the power of 3 and get 64.

$$36-64+5\left(3-5\right)^{3}$$

Subtract 64 from 36 to get -28.

$$-28+5\left(3-5\right)^{3}$$

Subtract 5 from 3 to get -2.

$$-28+5\left(-2\right)^{3}$$

Calculate -2 to the power of 3 and get -8.

$$-28+5\left(-8\right)$$

Multiply 5 and -8 to get -40.

$$-28-40$$

Subtract 40 from -28 to get -68.

$$-68$$

Factor

$$-68$$