Solve 3^2[5+3(2+4)-1]+sqrt{25}

$$3 ^ { 2 } [ 5 + 3 ( 2 + 4 ) - 1 ] + \sqrt { 25 }$$

Evaluate

$$203$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9\left(5+3\left(2+4\right)-1\right)+\sqrt{25}$$

Add 2 and 4 to get 6.

$$9\left(5+3\times 6-1\right)+\sqrt{25}$$

Multiply 3 and 6 to get 18.

$$9\left(5+18-1\right)+\sqrt{25}$$

Add 5 and 18 to get 23.

$$9\left(23-1\right)+\sqrt{25}$$

Subtract 1 from 23 to get 22.

$$9\times 22+\sqrt{25}$$

Multiply 9 and 22 to get 198.

$$198+\sqrt{25}$$

Calculate the square root of 25 and get 5.

$$198+5$$

Add 198 and 5 to get 203.

$$203$$

Factor

$$7\times 29$$