Solve 3^2+x^2=(4-x)^2

$$3 ^ { 2 } + x ^ { 2 } = ( 4 - x ) ^ { 2 }$$

Solve for x

$$x=\frac{7}{8}=0.875$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$9+x^{2}=\left(4-x\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4-x\right)^{2}.

$$9+x^{2}=16-8x+x^{2}$$

Add 8x to both sides.

$$9+x^{2}+8x=16+x^{2}$$

Subtract x^{2} from both sides.

$$9+x^{2}+8x-x^{2}=16$$

Combine x^{2} and -x^{2} to get 0.

$$9+8x=16$$

Subtract 9 from both sides.

$$8x=16-9$$

Subtract 9 from 16 to get 7.

$$8x=7$$

Divide both sides by 8.

$$x=\frac{7}{8}$$