Solve 3^{2}+3^2*2^3+(sqrt{44})^2-(sqrt{81})^2

$$3 ^ { 2 } + 3 ^ { 2 } \times 2 ^ { 3 } + ( \sqrt { 44 } ) ^ { 2 } - ( \sqrt { 81 } ) ^ { 2 }$$

Evaluate

$$44$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9+3^{2}\times 2^{3}+\left(\sqrt{44}\right)^{2}-\left(\sqrt{81}\right)^{2}$$

Calculate 3 to the power of 2 and get 9.

$$9+9\times 2^{3}+\left(\sqrt{44}\right)^{2}-\left(\sqrt{81}\right)^{2}$$

Calculate 2 to the power of 3 and get 8.

$$9+9\times 8+\left(\sqrt{44}\right)^{2}-\left(\sqrt{81}\right)^{2}$$

Multiply 9 and 8 to get 72.

$$9+72+\left(\sqrt{44}\right)^{2}-\left(\sqrt{81}\right)^{2}$$

Add 9 and 72 to get 81.

$$81+\left(\sqrt{44}\right)^{2}-\left(\sqrt{81}\right)^{2}$$

The square of \sqrt{44} is 44.

$$81+44-\left(\sqrt{81}\right)^{2}$$

Add 81 and 44 to get 125.

$$125-\left(\sqrt{81}\right)^{2}$$

The square of \sqrt{81} is 81.

$$125-81$$

Subtract 81 from 125 to get 44.

$$44$$

Factor

$$2^{2}\times 11$$