Solve 3^{2}+2^5*4-3^3*3+24:2^3-5^2*2

$$3 ^ { 2 } + 2 ^ { 5 } \times 4 - 3 ^ { 3 } \times 3 + 24 : 2 ^ { 3 } - 5 ^ { 2 } \times 2$$

Evaluate

$$9$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$3^{2}+2^{5}\times 4-3^{4}+\frac{24}{2^{3}}-5^{2}\times 2$$

Calculate 3 to the power of 2 and get 9.

$$9+2^{5}\times 4-3^{4}+\frac{24}{2^{3}}-5^{2}\times 2$$

Calculate 2 to the power of 5 and get 32.

$$9+32\times 4-3^{4}+\frac{24}{2^{3}}-5^{2}\times 2$$

Multiply 32 and 4 to get 128.

$$9+128-3^{4}+\frac{24}{2^{3}}-5^{2}\times 2$$

Add 9 and 128 to get 137.

$$137-3^{4}+\frac{24}{2^{3}}-5^{2}\times 2$$

Calculate 3 to the power of 4 and get 81.

$$137-81+\frac{24}{2^{3}}-5^{2}\times 2$$

Subtract 81 from 137 to get 56.

$$56+\frac{24}{2^{3}}-5^{2}\times 2$$

Calculate 2 to the power of 3 and get 8.

$$56+\frac{24}{8}-5^{2}\times 2$$

Divide 24 by 8 to get 3.

$$56+3-5^{2}\times 2$$

Add 56 and 3 to get 59.

$$59-5^{2}\times 2$$

Calculate 5 to the power of 2 and get 25.

$$59-25\times 2$$

Multiply 25 and 2 to get 50.

$$59-50$$

Subtract 50 from 59 to get 9.

$$9$$

Factor

$$3^{2}$$