Solve 3^2+2^2=x^2

$$3 ^ { 2 } + 2 ^ { 2 } = x ^ { 2 }$$

Solve for x

$$x=\sqrt{13}\approx 3.605551275$$

$$x=-\sqrt{13}\approx -3.605551275$$

Steps by Finding Square Root

Calculate 3 to the power of 2 and get 9.

$$9+2^{2}=x^{2}$$

Calculate 2 to the power of 2 and get 4.

$$9+4=x^{2}$$

Add 9 and 4 to get 13.

$$13=x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$x^{2}=13$$

Take the square root of both sides of the equation.

$$x=\sqrt{13} x=-\sqrt{13}$$

Steps Using the Quadratic Formula

Calculate 3 to the power of 2 and get 9.

$$9+2^{2}=x^{2}$$

Calculate 2 to the power of 2 and get 4.

$$9+4=x^{2}$$

Add 9 and 4 to get 13.

$$13=x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$x^{2}=13$$

Subtract 13 from both sides.

$$x^{2}-13=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -13 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-13\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-13\right)}}{2}$$

Multiply -4 times -13.

$$x=\frac{0±\sqrt{52}}{2}$$

Take the square root of 52.

$$x=\frac{0±2\sqrt{13}}{2}$$

Now solve the equation x=\frac{0±2\sqrt{13}}{2} when ± is plus.

$$x=\sqrt{13}$$

Now solve the equation x=\frac{0±2\sqrt{13}}{2} when ± is minus.

$$x=-\sqrt{13}$$

The equation is now solved.

$$x=\sqrt{13} x=-\sqrt{13}$$