Solve 3^2+(8+3)^2=AB^2

$$3 ^ { 2 } + ( 8 + 3 ) ^ { 2 } = A B ^ { 2 }$$

Solve for A

$$A=\frac{130}{B^{2}}$$

$$B\neq 0$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$9+\left(8+3\right)^{2}=AB^{2}$$

Add 8 and 3 to get 11.

$$9+11^{2}=AB^{2}$$

Calculate 11 to the power of 2 and get 121.

$$9+121=AB^{2}$$

Add 9 and 121 to get 130.

$$130=AB^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$AB^{2}=130$$

The equation is in standard form.

$$B^{2}A=130$$

Divide both sides by B^{2}.

$$\frac{B^{2}A}{B^{2}}=\frac{130}{B^{2}}$$

Dividing by B^{2} undoes the multiplication by B^{2}.

$$A=\frac{130}{B^{2}}$$

Solve for B

$$B=\sqrt{\frac{130}{A}}$$

$$B=-\sqrt{\frac{130}{A}}\text{, }A>0$$