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1,06^{x}=3
Swap sides so that all variable terms are on the left hand side.
\log(1,06^{x})=\log(3)
Take the logarithm of both sides of the equation.
x\log(1,06)=\log(3)
The logarithm of a number raised to a power is the power times the logarithm of the number.
x=\frac{\log(3)}{\log(1,06)}
Divide both sides by \log(1,06).
x=\log_{1,06}\left(3\right)
By the change-of-base formula log(a)/log(b)=log(b,a).