Solve 3=(-5a^2)(2-y)

$$3 = ( - 5 a ^ { 2 } ) ( 2 - y )$$

Solve for y

$$y=2+\frac{3}{5a^{2}}$$

$$a\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply -5a^{2} by 2-y.

$$3=-10a^{2}+5a^{2}y$$

Swap sides so that all variable terms are on the left hand side.

$$-10a^{2}+5a^{2}y=3$$

Add 10a^{2} to both sides.

$$5a^{2}y=3+10a^{2}$$

The equation is in standard form.

$$5a^{2}y=10a^{2}+3$$

Divide both sides by 5a^{2}.

$$\frac{5a^{2}y}{5a^{2}}=\frac{10a^{2}+3}{5a^{2}}$$

Dividing by 5a^{2} undoes the multiplication by 5a^{2}.

$$y=\frac{10a^{2}+3}{5a^{2}}$$

Divide 3+10a^{2} by 5a^{2}.

$$y=2+\frac{3}{5a^{2}}$$

Solve for a

$$a=\frac{\sqrt{-\frac{15}{2-y}}}{5}$$

$$a=-\frac{\sqrt{-\frac{15}{2-y}}}{5}\text{, }y>2$$